Carbohydrates are naturally occurring organic compounds containing carbon, hydrogen and oxygenwith oxygen in the ratio 1:2 as in water. The general molelcular formula of carbohydrates is Cx(H2O)y or CxH2yOy. Carbohydrates are generally polydroxyl aldehydes, ketones or any compound that on hydrolysis yields any of the polyhydroxides. They are synthesized in green plants by photosynthesis.
CLASSIFICATION OF CARBOHYDRATES
Carbohydrate
Simple sugar Complex sugar
(polysaccharides)
Monosaacharide Disacharides e.g. starch cellulose
e.g. glucose e.g sucrose
EVALUATION
- Define carbohydrates.
- State one example each of simple sugar and complex sugar.
MONOSAACHARIDES
Monosaacharides are simple sugar with three to six carbon atoms per molecule. The most common and important of these are the ones with six carbon atoms per molecule called the HEXOSES. They have the same molecular formula C6H12O6 but different spatial arrangement. Examples include glucose, fructose, galatose and mannose.
GLUCOSE (C6H12O6)
Glucose, commonly known as grape sugar or dextrose, is present in grapes, in honey and the sap of plants.
Glucose is synthesized by green plants during photosynthesis.
PREPARATION:- Glucose can be prepared in the laboratory by the acid hydrolysis of starch.
The starch is heated with dilute hydrochloric acid or tetraoxosulphate VI acid. The acid functioning as hydrolyzing agent in the reaction.
(C6H10O6)n nH2O nC6H12O6
Starch Dil H2SO4 glucose
Physical properties
- It is a white crystalline solid.
- It is soluble in water.
- It has sweet taste.
Chemical properties
- It dehydrates to black residue of carbon when with conc. H2SO4
C6H12O6 6C + 6H2O
- It is a strong reducing agent. This is due to the presence of the –CHO group in the molecule.
- It is readily fermented to ethanol and carbon VI oxide by the enzyme (ZYMASE) in yeast.
TEST: Add a few drops of Fehling’s solution to 5cm3 of glucose solution in a test tube. A brick- red precipitate is obtained on boiling.
GLUCOSE STRUCTURAL FORMULA:
H
C = O the functional groups in the
H C H molecule are:
HO C O -CHO and OH
H C OH But -CHO determines the
H C OH chemical properties
OH C H
H
FRUCTOSE (C6H12O6)
An isomer of glucose is fructose. Fructose is a non-reducing sugar (it contains the >CO group)
FRUCTOSE STRUCTURAL FORMULA
H
H C OH The functional groups in the molecule are:
C = -C=O and –OH
Chemical properties
HO C H
H C OH
H C OH
H C OH
EVALUATION
- State two (2) physical properties of starch.
- Give difference between glucose and starch.
DISACCHARIDES
Disaccharides are simple sugar containing two molecules of monosaccharide per molecules. Their general molecular formula is C12H22O11. Some important disaccharides and the component monosaccharide are;
DISACCHARIDE COMPONENT MONOSACCHARIDES
Sucrose (cane sugar) Glucose + fructose
Lactose (milk sugar) Glucose + galactose
Maltose (malt sugar) Glucose + glucose
SUCROSE
This is the common granulated sugar used at home to sweeten food. It occurs naturally in plant and fruits e.g. pineapple, carrots sorghum, sap and sugar cane.
Preparation: Sucrose is prepared industrially by;
- Extraction of juice from sugar cane,
- Concentration of the juice by evaporation,
- Crystallization of the solid sugar from the concentrated juice and
- Filtration of sugar crystals from the molasses.
PHYSICAL PROPERTIES:
- It is a white crystalline solid.
- It is dissolves readily in water.
- It has sweet taste.
CHEMICAL PROPERTIES:
- It chars by dehydration to a black residue of carbon on addition of Conc. H2SO4.
C12H22O11 12C + 6H2O
- It undergoes hydrolysis to equal quantity of glucose and fructose when boiled with dil.
H2SO4 or HCL (aq)
- It undergoes inversion under the influence of invertase in yeast
Sucrose invertase Glucose + Fructose
- It is non-reducing sugar.
TEST:
Glucose gives a red precipitate with freshly prepared Seliwanoff’s reagent.
USES
- For sweetening foods and beverages.
- For ethanol production by fermentation.
POLYSACCHARIDES
Polysaccharides are a group of complex carbohydrates composed of very long chains of monosaccharide linked together by condensation polymerization.
Monosaccharide condensation polysaccharides + n/2 water
Hydrolysis
Some important examples of polysaccharides are starch, glycogen, and cellulose. The general molecular formula of polysaccharides is (C6H10O5)n
EVALUATION
- Name three disaccharides and the component monosaccharide.
- Describe what would be observed on addition of Conc. H2SO4 to sucrose.
PROTEIN
Proteins are made up of polypetides chains. Polypeptide chains are products of condensation polymerization of amino acid molecules. The condensation polymerization of amino acid is the interaction between amino groups, -NH2, and Carboxyl groups, -COOH, to form the polypeptide chain.
A polypeptide chain:
H O H O H
O
+H3 N C C [N C C] +nN C
O
R H R H R
Amino end dipeptide Carboxyl end
OCCURRENCE
Proteins are found in living cells where they perform different functions. Examples are hemoglobin, collagen and insulin, ribonucleic. The structure have cross linkage between chains which are called disulphide bridges or disulphide cross linkages.
Properties
- They are denatured easily at a temperature above 400C by variation in PH and by certain organic solvents and chemical reagents.
- Proteins are hydrolyzed to give amino acids by boiling with dilute acids (e.g. HCI) and alkalis or using enzymes.
Uses
- They are used for building up of tissues and repairing of worn-out tissues in the body.
- They are necessary for growth especially in infants.
Tests
- Million’s test – A white ppt. is form when a few drops of Million’s reagent are added to some
egg-white in a test-tube. The white ppt. turns brick red on heating (indicating the presence of proteins).
- Biuret test: when few drops of dilute NaOH solution is added to some egg white solution in
a test tube, and 1% CUSO4 solution is added drop by drop and the test solution is shaken
vigorously after each drop. A violet colour is seen indicating a positive test for proteins.
- Proteins form an intense yellow colour with a few drops of conc. HNO3 acid.
EVALUATION
- Explain a chemical test for proteins.
- What is the product of hydrolysis of proteins?
AMINO-ACIDS
Amino acids are the basic structural units of proteins.
The functional groups in amino acids are amino group (-NH2) and a carboxyl group (-COOH)
General structure
NH2 α carbon
H C COOH
R
EVALUATION
- Give the functional group of protein.
- Draw the structural formula of a polypeptide.
α carbons are carbons in amino acids to which the functional groups are attached.
Examples – glycine, phenylalnine, alanine etc. Amino acids are mainly in form of dipolar ions in neutral solution (zwitterions).
EVALUATION
- Name the functional groups present in amino acids molecule.
- What are proteins?
- State two properties of protein.
WEEKEND ASSIGNMENT
- One of the following is not a monosaccharide
- glucose B. maltose C. fructose D. maltose
- The product obtained when sucrose is treated with dil. HCI are
- glucose and galatose B. fructose and galatose C. glucose and fructose D. glucose
- Which of the following is a reducing sugar?
- fructose B. glucose C. sucrose D. ribose
- Which one of these substances is not a polysaccaharides?
- lactose B. starch C. cellulose D. mannose
- Few drops of conc HNO3 is added to a solution and an intense yellow colour is obtained,
then the solution contained.
- proteins B. carbohydrates C. fat D. oil
THEORY
- Explain a laboratory test for proteins.
2a. What are carbohydrates?
- Name the component monosaccaharide of
(i) sucrose (ii) maltose.
See also
NATURAL AND SYNTHETIC POLYMERS